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-2h^2-56h-66=0
a = -2; b = -56; c = -66;
Δ = b2-4ac
Δ = -562-4·(-2)·(-66)
Δ = 2608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2608}=\sqrt{16*163}=\sqrt{16}*\sqrt{163}=4\sqrt{163}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{163}}{2*-2}=\frac{56-4\sqrt{163}}{-4} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{163}}{2*-2}=\frac{56+4\sqrt{163}}{-4} $
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